Rrb ntpc exam CBT 1 Normalisation formal

Notice Railway

To the Centralized Employment Notification (CEN) No.01/2019

for recruitment of various Non-Technical Popular categories Graduate and

Under Graduate Posts published on official websites of RRBs on 28.02.2019

Vide Para 14.1 of detailed CEN-01/2019, a formula for calculation of normalized marks

for multi session papers has been published. The formula has been modified as mentioned

below and will be adopted for normalization.

= normalized marks of jth candidate in the ith shift

Mt

g

= is the average marks of the top 0.1% of the candidates considering all

shifts (number of candidates will be rounded-up)

Mqg = is the sum of mean and standard deviation marks of the candidates in

the examination considering all shifts

Mti = is the average marks of the top 0.1% of the candidates in the ith shift

(number of candidates will be rounded up)

Miq = is the sum of mean marks and standard deviation of the ith shift

Mij = is the actual marks obtained by the jth candidate in the ith shift

Mq

gm = is the sum of mean marks of candidates in the shift having maximum mean

and standard deviation of marks of candidates in the examination

considering all.

Rrb ntpc exam CBT 1 ke liye Normalization formal

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